GanzChroma 0314
Oh man, where do I even start with this one? So there I was, scrolling through the sea of reddit meme posts, when I stumble upon someone claiming to be a “VFX Supervisor - 20 years experience” on Reddit.
Now, don’t get me wrong, experience is great. But on a platform where everyone’s got usernames like "PixelWizard42" or "FlameThrower99," can we really take these claims at face value?
I mean, come on! A supervisor with two decades of experience, casually dropping into a Reddit thread to flex? That’s like seeing a Michelin-star chef bragging about their ramen cooking skills in a college dorm forum.
Something just doesn’t add up, right?
Reddit is the wild west of the internet where trolls, geniuses, and conspiracy theorists all roam free. It’s a place where anonymity reigns supreme. You could be chatting with an actual VFX supervisor or someone's uncle Dave who just discovered After Effects last week.
The point is, you never know! And that’s kinda the beauty of it too, isn’t it?
Making bold claims without any receipts...well, it’s a bit like yelling “I’m Batman!” in a crowded room. Sure, you could be Bruce Wayne, but you’re more likely just a guy with a blanket for a cape. 🦇
Let's not discredit the dude entirely. Let’s say, hypothetically, they are a VFX Supervisor with 20 years under their belt. What are they doing flexing in a comment section?
If you’ve got that kind of resume, wouldn’t you be too busy juggling work and life to post on Reddit? 🤷
In this new world, actions speak louder than words or usernames. What is their Social Credit?
Claims without faces are just noise. Meanwhile, at Alpha Chromatica, You know our names, our quirks, what comics we’re reading, and even our favorite snacks. We’re more than just titles and years of experience, we’re real people with real stories, not just random usernames.
So, the next time you see someone flexing credentials in a comment section, ask yourself: would they rather be known for their work or their Reddit karma? At Alpha Chromatica, we choose the work every time.